Writing Electron Configurations and Orbital Notations

An electron configuration lists the subshells occupied by the electrons of an atom, with the number of electrons shown as a superscript, such as 1s2 2s2 2p4 for oxygen, while an orbital notation (orbital diagram) shows each orbital as a box and each electron as an arrow. In brief: to write a configuration, fill the subshells in the order 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p until all electrons are placed, and use the noble gas shorthand, for example [Ne] 3s2 3p5 for chlorine, to save space.

Electron configurations summarize an atom’s electronic structure, and from them chemists predict valence electrons, bonding, ion charges and magnetism. This article explains the step-by-step method, the shorthand notation, orbital diagrams, how to write configurations for ions and exceptions, shows the configurations of the first 36 elements in a table, works through examples and gives some history.

How do you write an electron configuration?

  1. Find the number of electrons: for a neutral atom, it equals the atomic number.
  2. Write the subshells in the filling order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.
  3. Fill each subshell to its capacity: s holds 2, p holds 6, d holds 10 and f holds 14 electrons.
  4. Stop when all electrons are placed. The last subshell may be only partly filled.
  5. Check that the superscripts add up to the total number of electrons.
  6. Check for known exceptions (Cr, Cu and others).

What is the noble gas shorthand?

The inner electrons are the same as those of the previous noble gas, so you can replace them by the noble gas symbol in square brackets. Sodium, with 11 electrons, is 1s2 2s2 2p6 3s1, where the first ten electrons are the same as neon, so the shorthand is [Ne] 3s1. The electrons that follow the noble gas core are the valence electrons (and, for transition metals, the d electrons).

How do you draw an orbital diagram?

Draw a box for each orbital: one for each s subshell, three for p, five for d and seven for f. Group the boxes by subshell and label them. Place arrows in the boxes following Hund’s rule and the Pauli principle: fill each box in a subshell with a single upward arrow first, and then add downward arrows to pair them. For nitrogen: 1s [↑↓], 2s [↑↓], 2p [↑] [↑] [↑]. In plain text, the diagram may be shown as 1s: ↑↓ | 2s: ↑↓ | 2p: ↑ ↑ ↑.

N ↑ ↓ 1s ↑ ↓ 2s ↑ ↑ ↑ 2p

Electron configurations of the first 36 elements

Ground-state electron configurations, Z = 1 to 18
Z Element Full configuration Shorthand
1H1s11s1
2He1s21s2
3Li1s2 2s1[He] 2s1
4Be1s2 2s2[He] 2s2
5B1s2 2s2 2p1[He] 2s2 2p1
6C1s2 2s2 2p2[He] 2s2 2p2
7N1s2 2s2 2p3[He] 2s2 2p3
8O1s2 2s2 2p4[He] 2s2 2p4
9F1s2 2s2 2p5[He] 2s2 2p5
10Ne1s2 2s2 2p6[He] 2s2 2p6
11Na1s2 2s2 2p6 3s1[Ne] 3s1
12Mg1s2 2s2 2p6 3s2[Ne] 3s2
13Al1s2 2s2 2p6 3s2 3p1[Ne] 3s2 3p1
14Si1s2 2s2 2p6 3s2 3p2[Ne] 3s2 3p2
15P1s2 2s2 2p6 3s2 3p3[Ne] 3s2 3p3
16S1s2 2s2 2p6 3s2 3p4[Ne] 3s2 3p4
17Cl1s2 2s2 2p6 3s2 3p5[Ne] 3s2 3p5
18Ar1s2 2s2 2p6 3s2 3p6[Ne] 3s2 3p6
Ground-state electron configurations, Z = 19 to 36
Z Element Shorthand configuration Note
19K[Ar] 4s1–
20Ca[Ar] 4s2–
21Sc[Ar] 3d1 4s2–
22Ti[Ar] 3d2 4s2–
23V[Ar] 3d3 4s2–
24Cr[Ar] 3d5 4s1Exception
25Mn[Ar] 3d5 4s2–
26Fe[Ar] 3d6 4s2–
27Co[Ar] 3d7 4s2–
28Ni[Ar] 3d8 4s2–
29Cu[Ar] 3d10 4s1Exception
30Zn[Ar] 3d10 4s2–
31Ga[Ar] 3d10 4s2 4p1–
32Ge[Ar] 3d10 4s2 4p2–
33As[Ar] 3d10 4s2 4p3–
34Se[Ar] 3d10 4s2 4p4–
35Br[Ar] 3d10 4s2 4p5–
36Kr[Ar] 3d10 4s2 4p6–

By convention, the 3d subshell is written before 4s in the shorthand for atoms after calcium, because 3d is part of the third shell, although 4s is filled first.

How do you write the configuration of an ion?

For a cation, remove electrons from the subshell with the highest principal quantum number n first. This means that for transition metals the 4s electrons are removed before the 3d electrons, though 4s is filled first. For an anion, add electrons following the usual filling order.

Worked examples

  1. Sulfur (16 electrons). 1s2 (2), 2s2 (4), 2p6 (10), 3s2 (12), 3p4 (16). Shorthand: [Ne] 3s2 3p4. Valence electrons: 2 + 4 = 6.
  2. Orbital diagram of sulfur. 3s: ↑↓; 3p: ↑↓ ↑ ↑. There are 2 unpaired electrons.
    S [Ne] ↑ ↓ 3s ↑ ↓ ↑ ↑ 3p
  3. Manganese (25 electrons). [Ar] 3d5 4s2. Check: 18 + 5 + 2 = 25 ✓. The 3d subshell is half-filled with 5 unpaired electrons.
    Mn [Ar] ↑ ↓ 4s ↑ ↑ ↑ ↑ ↑ 3d
  4. Copper(II) ion. Copper is [Ar] 3d10 4s1. Cu2+ loses the 4s electron and one 3d electron: [Ar] 3d9. The ion has 1 unpaired electron and is paramagnetic, and its compounds are often blue.
    Cu2+ [Ar] ↑ ↓ ↑ ↓ ↑ ↑ ↑ 3d
  5. Identify the element. The configuration [Kr] 5s2 4d10 5p2 has 36 + 2 + 10 + 2 = 50 electrons, so it is tin (Sn). It has 4 valence electrons (5s2 5p2), so it is in group 14.
  6. Isoelectronic species. S2−, Cl−, K+ and Ca2+ all have 18 electrons and the configuration [Ne] 3s2 3p6, the same as argon.

How does the periodic table help?

The shape of the periodic table follows the filling order. Groups 1 and 2 form the s-block, groups 13 to 18 the p-block, the transition metals the d-block and the lanthanides and actinides the f-block. To write a configuration, count the position of the element in the table: the period number gives the shell, and counting across the blocks gives the number of electrons in the last subshell. For example, selenium is in period 4, group 16, so it ends in 4p4 (the fourth element of the p-block).

How did this notation develop?

Niels Bohr and Wolfgang Pauli worked on electron shell structure in the early 1920s. The spdf notation comes from spectroscopy, and the systematic electron configurations were developed for each element as the quantum theory was refined in the 1920s. The noble gas shorthand became popular because it highlights the valence electrons. The accepted configurations of many heavy elements are determined by experiment and calculation, and for some of them, such as lawrencium, the assignment is subject to continuing study.

Which mistakes are common?

Mistake 1: Making the superscripts the wrong total

Always check that the sum of the superscripts equals the number of electrons.

Mistake 2: Removing 3d electrons first when forming transition metal ions

The 4s electrons are removed first.

Mistake 3: Forgetting the exceptions

Chromium and copper have a half-filled or full 3d subshell, with only one 4s electron.

Mistake 4: Writing p7 or d11

The capacities are 6 for p, 10 for d and 14 for f.