The Cahn-Ingold-Prelog R/S Configuration System

The Cahn–Ingold–Prelog (CIP) system assigns the absolute configuration of a stereocenter as R (rectus, clockwise) or S (sinister, counterclockwise) by ranking the four attached groups by priority and viewing the molecule with the lowest-priority group pointing away from the viewer. In brief: in (S)-lactic acid the priorities are OH > COOH > CH3 > H, and with the hydrogen at the back, the sequence OH → COOH → CH3 runs counterclockwise.

Names such as “(R)-2-butanol” or “(2S,3R)-threonine” show the precise spatial arrangement at each stereocenter. The R/S system gives a name for every enantiomer, unlike the older D/L system, which is limited to sugars and amino acids. This article explains the priority rules, the procedure for assigning R and S, shows a table of group priorities, gives worked examples including a Fischer projection, and clarifies what R and S do not tell.

What are the priority rules?

  1. Atomic number: compare the atoms directly attached to the stereocenter. The higher the atomic number, the higher the priority (I > Br > Cl > S > F > O > N > C > H). For isotopes, the higher mass number has priority (D > H).
  2. Tie at the first atom: compare the sets of atoms attached to those atoms, working outward, one sphere at a time. Compare the atoms in order of decreasing atomic number: the first point of difference decides. For –CH2OH (O, H, H) against –CH2CH3 (C, H, H): O > C, so –CH2OH has the higher priority.
  3. Multiple bonds: a double or triple bond is treated as if each bond led to a separate atom (duplicate atoms are added): –CH=CH2 counts as (C, C, H) on the first carbon, and –CHO as (O, O, H), and –C≡N as (N, N, N).
  4. Continue outward from the first point of difference, always comparing the highest-ranked branches first.

Priorities of common groups

Priority order of some groups (highest first) and the atoms on which it is based
Rank Group Attached atom set Reason
1–I, –Br, –ClI, Br, ClHighest atomic numbers (53, 35, 17)
2–OHOAtomic number 8
3–NH2NAtomic number 7
4–COOH(O, O, O)Carbon with three oxygens
5–CHO(O, O, H)Carbon with two oxygens and H
6–CH2OH(O, H, H)Carbon with one oxygen
7–C6H5 (phenyl)(C, C, C)Carbon with three carbons
8–CH=CH2(C, C, H)Carbon with two carbons (duplicate)
9–CH2CH3(C, H, H)Carbon with one carbon
10–CH3(H, H, H)Carbon with only hydrogens
11–HHAtomic number 1

In the table, the halogens, –OH and –NH2 (the heteroatoms) precede the carbon groups when they are attached directly to the stereocenter. Among the halogens and heteroatoms, the order is by atomic number (I, Br, Cl, S, F, O, N). Note that a group such as –CH2Cl, in which the first atom is carbon, ranks as a carbon group with the set (Cl, H, H), and thus above –COOH (O, O, O), because Cl is compared first with O.

How do you assign R or S?

  1. Identify the stereocenter and its four groups.
  2. Assign priorities 1 to 4 (1 = highest) with the rules above.
  3. Orient the molecule so that the group of lowest priority (4, usually H) points away from you.
  4. Look at the three remaining groups, and trace the path from 1 to 2 to 3.
  5. If the path is clockwise, the configuration is R. If it is counterclockwise, it is S.
  6. If the lowest-priority group points toward you, determine the direction and reverse the result.

For molecules with several stereocenters, each is assigned independently, and the configurations are given in the name with locants: (2R,3S)-2,3-dibromobutane. The descriptor is part of the name of the compound.

Worked examples

Example 1: bromochlorofluoromethane

CHFClBr. Priorities: Br (1) > Cl (2) > F (3) > H (4). With the H pointing away, if Br → Cl → F is clockwise, the compound is (R)-bromochlorofluoromethane; if it is counterclockwise, it is (S).

Example 2: lactic acid

The stereocenter in lactic acid, CH3CH(OH)COOH, has the groups OH (O), COOH (O,O,O), CH3 (H,H,H) and H. Priorities: OH (1) > COOH (2) > CH3 (3) > H (4). Muscle produces (S)-(+)-lactic acid, also called L-lactic acid. For the (S) form, with H at the back, the sequence OH → COOH → CH3 runs counterclockwise. The (R)-enantiomer is (−)-lactic acid. This shows that the sign of the rotation is not connected with R or S.

OHCOOHCH3 OHCH3COOH 123 123 SR

Example 3: alanine

L-Alanine has the groups NH2 (1), COOH (2), CH3 (3) and H (4), so the priorities are N > COOH > CH3 > H. Natural L-alanine is (S). Almost all natural L-amino acids are (S), the exception being cysteine, which is (R), because the –CH2SH group (S, H, H) has a higher priority than –COOH (O, O, O), since S has a higher atomic number than O.

Example 4: butan-2-ol

The groups on C2 are OH (1), CH2CH3 (2), CH3 (3) and H (4). The ethyl group (C, H, H) has higher priority than methyl (H, H, H). (R)-Butan-2-ol is the enantiomer in which OH → C2H5 → CH3 runs clockwise with H at the back.

Example 5: ranking a tricky case

For the stereocenter of 1-phenylethanol, the groups are OH, C6H5 (C, C, C), CH3 (H, H, H) and H. Priorities: OH > phenyl > CH3 > H.

How do you assign from a Fischer projection?

In a Fischer projection, the horizontal bonds point toward the viewer and the vertical bonds point away. If the lowest-priority group (H) is on a horizontal bond (toward the viewer), trace 1 → 2 → 3 and then reverse the result. If H is on a vertical bond, the direction read from the projection is the correct one.

Example: D-glyceraldehyde. The projection has CHO at the top, CH2OH at the bottom, OH on the right and H on the left. Priorities: OH (1) > CHO (2) > CH2OH (3) > H (4). Going from OH (right) to CHO (top) to CH2OH (bottom) is counterclockwise, which would be S. But H is on a horizontal bond, so the result is reversed: the configuration is R. D-Glyceraldehyde is (R)-glyceraldehyde.

CHOCH2OH HOH 213 R

What do R and S not tell you?

Who developed the system?

Robert Cahn, Christopher Ingold and Vladimir Prelog developed the sequence rules in the 1950s, and published them in 1956, with a final version in 1966. Before this, the absolute configuration of molecules was only known relative to a standard: Emil Fischer assigned in 1891 the D configuration to (+)-glyceraldehyde, arbitrarily, with a 50 % chance of being right. In 1951 Johannes Bijvoet showed by X-ray diffraction with anomalous scattering, using sodium rubidium tartrate, that Fischer’s guess was correct. Prelog shared the Nobel Prize in Chemistry in 1975 for his work on the stereochemistry of organic molecules and reactions.

Which mistakes are common?