Salt Hydrolysis and Aqueous pH

Salt hydrolysis is the reaction of the ions of a salt with water that changes the pH: the anion of a weak acid makes the solution basic, the cation of a weak base (or a small, highly charged metal cation) makes it acidic, and ions of strong acids and strong bases do not affect the pH. In brief: a 0.100 mol/L solution of sodium acetate has pH 8.87, ammonium chloride has pH 5.13, and sodium chloride has pH 7.00.

When a salt dissolves, its ions can act as weak acids or weak bases. This article gives rules to predict whether a salt solution is acidic, basic or neutral, shows how to calculate the pH using Kw, tabulates typical results, explains the case of salts with both ions hydrolyzing, works through examples and gives some history.

What are the rules?

How do anions hydrolyze?

The acetate ion takes a proton from water: CH3COO− + H2O ⇌ CH3COOH + OH−. Because Ka of acetic acid is 1.8 × 10−5, Kb = 5.6 × 10−10. The weaker the parent acid, the more basic its anion. Carbonate (Kb = 2.1 × 10−4) is much more basic than acetate.

How do cations hydrolyze?

The ammonium ion gives up a proton: NH4+ + H2O ⇌ NH3 + H3O+, Ka = 5.6 × 10−10. Hydrated metal ions are acidic since the metal polarizes the O–H bonds of coordinated water.

pH of salt solutions

Calculated pH of 0.100 mol/L salt solutions at 25 °C
SaltHydrolyzing ionKpH
NaClNone–7.00
NH4ClNH4+Ka = 5.6 × 10−105.13
CH3COONaCH3COO−Kb = 5.6 × 10−108.87
NaCNCN−Kb = 1.6 × 10−511.10
Na2CO3CO32−Kb = 2.1 × 10−411.65
NaHCO3Amphiprotic–about 8.34
AlCl3Al(H2O)63+Ka ≈ 1.4 × 10−5about 2.9
0 2 4 6 8 10 12 14 pH AlCl3 NH4Cl NaCl CH3COONa NaCN Na2CO3

What if both ions hydrolyze?

Compare Ka of the cation with Kb of the anion. If Ka > Kb, the solution is acidic; if Kb > Ka, basic; if equal, neutral. Ammonium acetate: Ka(NH4+) = 5.6 × 10−10 and Kb(CH3COO−) = 5.6 × 10−10, so pH ≈ 7. Ammonium cyanide is basic (CN− is a stronger base than NH4+ is an acid), and ammonium fluoride is acidic.

Worked examples

  1. Sodium acetate, 0.100 mol/L. Kb = 5.6 × 10−10; [OH−] = √(5.6 × 10−10 × 0.100) = 7.5 × 10−6 mol/L; pOH 5.13; pH 8.87.
  2. Ammonium chloride, 0.100 mol/L. [H+] = √(5.6 × 10−10 × 0.100) = 7.5 × 10−6 mol/L; pH 5.13.
  3. Sodium carbonate, 0.100 mol/L. Kb1 = 1.0 × 10−14 ÷ 4.7 × 10−11 = 2.1 × 10−4. Solve x2 + 2.1 × 10−4x − 2.1 × 10−5 = 0: x = 4.5 × 10−3 mol/L; pOH 2.35; pH 11.65.
  4. Predict. KNO3 neutral; FeCl3 acidic; Na3PO4 basic (phosphate is the conjugate base of the weak acid HPO42−).
  5. Ka from Kb. For methylammonium, Ka = 1.0 × 10−14 ÷ 4.4 × 10−4 = 2.3 × 10−11.
  6. Percent hydrolysis. In example 1: 7.5 × 10−6 ÷ 0.100 × 100% = 0.0075%. Hydrolysis is small, but it shifts the pH by almost two units.

Where does hydrolysis matter?

The term hydrolysis was used in the 19th century for the reaction of salts with water, and Arrhenius and Ostwald gave a quantitative treatment in the 1880s and 1890s.

Which mistakes are common?

Mistake 1: Saying that all salts are neutral

Salts of weak acids or bases are not.

Mistake 2: Using Ka of the acid for the anion’s pH

Use Kb = Kw ÷ Ka.

Mistake 3: Hydrolyzing Cl− or Na+

They come from a strong acid and a strong base and do not react with water appreciably.

Mistake 4: Forgetting the highly charged metal ions

Fe3+ and Al3+ make solutions acidic.