Kinetic Theory and Molecular Pressure of Gases

The kinetic theory of gases explains the properties of an ideal gas by the motion of its molecules: the pressure results from molecular collisions with the walls, p = (1/3)(N/V)m⟨v2⟩, and the average translational kinetic energy of a molecule is (3/2)kT, so temperature is a measure of the molecular kinetic energy. In brief: the root-mean-square speed is vrms = √(3kT ÷ m) = √(3RT ÷ M). At 300 K, nitrogen molecules have vrms ≈ 517 m/s and hydrogen molecules ≈ 1,930 m/s. The speeds follow the Maxwell-Boltzmann distribution. Gases at the same temperature have the same average kinetic energy per molecule, regardless of mass.

Why does a gas exert pressure, and what does temperature mean at the molecular level? Kinetic theory links the microscopic motion of particles to the macroscopic quantities pressure and temperature. This guide states the assumptions of the model, derives the pressure, explains the meaning of temperature and the distribution of speeds, compares gases in a table, works through numerical examples and corrects common mistakes.

What are the assumptions of the model?

Real gases approach this ideal behavior at low pressure and high temperature, when the molecules are far apart and their intermolecular forces matter little.

How does the pressure arise?

When a molecule of mass m with a velocity component vx collides elastically with a wall perpendicular to the x-axis, its momentum changes by 2mvx. In a cubic box of side L, it hits the same wall every 2L ÷ vx seconds, so the average force is mvx2 ÷ L. Summing over all N molecules, and using ⟨vx2⟩ = ⟨v2⟩ ÷ 3 (since there is no preferred direction), the pressure on the wall (force per area L2) is

p = (1/3)(N/V) m⟨v2⟩ = (2/3)(N/V)⟨Ek⟩,

where ⟨Ek⟩ = ½m⟨v2⟩ is the mean translational kinetic energy. The pressure is proportional to the number density and to the mean kinetic energy of the molecules. In terms of the density, p = (1/3)ρ⟨v2⟩. Compression raises the pressure because molecules hit the walls more often; heating raises it because they hit harder and more often.

What does temperature mean?

Comparing the result with the ideal gas law, pV = NkT (k = 1.381 × 10−23 J/K is the Boltzmann constant), gives (2/3)N⟨Ek⟩ = NkT, so

⟨Ek⟩ = (3/2)kT.

The absolute temperature is proportional to the mean translational kinetic energy per molecule. At the same temperature, all ideal gases have the same average kinetic energy per molecule; the lighter molecules move faster. The root-mean-square speed is vrms = √⟨v2⟩ = √(3kT ÷ m) = √(3RT ÷ M), where M is the molar mass. At absolute zero, the translational motion would stop (classically). The internal energy of a monatomic ideal gas is U = (3/2)NkT = (3/2)nRT. For molecules with rotation and vibration, additional degrees of freedom store energy (equipartition: ½kT per quadratic degree of freedom).

What is the distribution of speeds?

The molecules in a gas do not all have the same speed: collisions constantly exchange energy. The Maxwell-Boltzmann distribution gives the fraction of molecules in each speed range: it rises from zero, peaks at the most probable speed vp = √(2kT ÷ m), and has a long tail toward high speeds. The mean speed is ⟨v⟩ = √(8kT ÷ πm) and vrms = √(3kT ÷ m), so vp < ⟨v⟩ < vrms in the ratio 1 : 1.13 : 1.22. Raising the temperature shifts the peak to a higher speed and broadens the distribution. The fast tail explains evaporation (the fastest molecules escape from a liquid), chemical reaction rates, and the loss of light gases from planetary atmospheres (the Earth cannot retain hydrogen and helium, but holds nitrogen and oxygen).

Distribution of nitrogen molecule speeds at 300 K and 600 K 0 500 1000 1500 0 0.5 1 1.5 2 Molecular speed (m/s) Fraction per m/s (10−3) vrms = 517 m/s 300 K 600 K
Distribution of speeds of nitrogen molecules, calculated from the Maxwell-Boltzmann formula. At 300 K (solid) the typical speed is a few hundred meters per second, and the root-mean-square speed is 517 m/s as in the worked example. At 600 K (dashed) the peak moves to higher speed, the curve broadens and it gets lower, because the areas under both curves are equal.

Molecular speeds compared

Root-mean-square speeds at 300 K
Gas Molar mass (g/mol) vrms (m/s)
Hydrogen (H2)2.0161,927
Helium (He)4.0031,367
Nitrogen (N2)28.0517
Oxygen (O2)32.0484
Carbon dioxide (CO2)44.0412

Worked example: speeds and energies

  1. Rms speed of nitrogen at 300 K. M = 0.0280 kg/mol: vrms = √(3 × 8.314 × 300 ÷ 0.0280) = √(2.672 × 105) = 517 m/s, about 1,860 km/h, higher than the speed of sound in air (347 m/s at 300 K), which is of the same order since sound is carried by molecular motion.
  2. Hydrogen. M = 0.002016 kg/mol: vrms = √(3 × 8.314 × 300 ÷ 0.002016) = 1,927 m/s, 3.7 times faster than nitrogen (= √(28.0 ÷ 2.016)).
  3. Mean kinetic energy. ⟨Ek⟩ = (3/2)kT = 1.5 × 1.381 × 10−23 × 300 = 6.2 × 10−21 J (0.039 eV) for any ideal gas at 300 K.
  4. Doubling the temperature. From 300 K to 600 K, the mean kinetic energy doubles, and vrms increases by √2 = 1.41, to 731 m/s for nitrogen.
  5. Pressure from number density. At 273.15 K and 101.3 kPa, the number density is N/V = p ÷ kT = 101,325 ÷ (1.381 × 10−23 × 273.15) = 2.69 × 1025 molecules per m3 (Loschmidt’s number). One mole occupies V = nRT ÷ p = 8.314 × 273.15 ÷ 101,325 = 0.0224 m3 = 22.4 L.
  6. Internal energy. The internal energy of 1.0 mol of a monatomic gas at 300 K: U = (3/2)RT = 1.5 × 8.314 × 300 = 3,741 J.
0 1,000 2,000 3,000 517 1,927 m/s

How was kinetic theory developed?

Daniel Bernoulli proposed in 1738 that gas pressure results from molecular collisions. The theory was developed by Rudolf Clausius (1857), James Clerk Maxwell, who derived the speed distribution in 1860, and Ludwig Boltzmann, who connected it with statistical mechanics in the 1870s. Albert Einstein’s explanation of Brownian motion in 1905, confirmed by Jean Perrin, convinced the remaining skeptics of the reality of molecules.

Which mistakes are common?

Mistake 1: Thinking that all molecules have the same speed

There is a distribution. The rms speed is a particular average.

Mistake 2: Using Celsius in the kinetic energy formula

T must be in kelvins.

Mistake 3: Believing that heavier gas molecules have higher kinetic energy

At the same temperature, the mean translational kinetic energy is equal. The heavier molecules are slower.

Mistake 4: Applying the model to dense gases without caution

At high pressure and low temperature, the molecular volume and the attractive forces matter (van der Waals corrections).